What Voltage is Necessary?

4. To store x₁ mJ of energy in an x₂ μF capacitor, what voltage is necessary?
x₁ and x₂ are some numbers.

Solution:
U = x₁ mJ = x₁ ∙ 10⁻³J
C = x₂ μF = x₂∙ 10⁻⁶ F
V²= 2U/C = 2x₁ ∙ 10⁻³J/(x₂∙ 10⁻⁶ F) = 2∙ 10³x₁/x₂ J/F
V=(2∙10³ x₁/x₂)⁰·⁵ V = 44.7(x₁/x₂)⁰∙⁵ V